I often struggle with puzzles… not this one. https://twitter.com/davidwees/status/544490638948196352/photo/1
Four digit number : k h t u (why those letters? ;))
Product of digits is not 0. (Fast conclusion: no digits zero.)
tu = h — very limited possibilities; product still has to be 9 or fewer but… that doesnt’ get me an answer. (Yes, I’m already using the teachable strategy: find *one* of ’em and build from that. )
Only odd digit = k … could be useful…
t + l = k
t is a square number — OKAY, here’s my starting point… that’s limited to 1, 4, or 9… and since it has to be even, it’s 4. Puzzle over.. then k is 5…
None of my digits are the same
I’m greater than 5000.
—————–
So: 5_4_ U must be 2 b/c it has to be even, so h must be 8. (last two ‘clues’ seem superflous…)
5842
… Of course, this has me pondering why this is “fun” for me — how much does working memory and extreme automaticity of basic things (evenness of numbers, that ‘answers’ have to be from 1-9 and ease of testign all possibilities without brain strain…)
… but I vowed to make an effort to dive into Desire2Lrn today, since classes and finals are over and student traffic will be minimal, so onward!
Resource Room Dot Net Blog 
Posted on December 15, 2014
0